Notes
1.  Special case of result in text.
2.  See the definition: should be exp(–/2).
3.  Since | zk | = exp(kLog | z |) = | z |k).
4.  For i1/3 = exp(
i/6 + 1/3.2ki), k = 0, 1, 2.
5.  Integer multiples of 2
i in the variable of exp give no new values.